Calculus Archive: Questions from May 20, 2023
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D6. Find \( y^{\prime} \) in terms of \( x \) and \( y \) by implicit differentiation if: (a) \( x^{2} y+x y^{-2}=2 \) (c) \( x y+\sqrt{x+y}=1 \) (b) \( \sec x \tan y+\sin x \cos y=1 \) (d) \( \sin (x2 answers -
Ejercicios: Trabaje presentando todos sus pocesos organizados que justifican su respuesta. 1) Evalúe a) \( \operatorname{csch}(\ln 3) \) b) \( \cosh (0) \) 2) Presente el procesos para hallar la deri2 answers -
y4 3) El largo de la curva x = 16 + 16 21 a) c) 211 16 2y² desde y = -2 hasta y = - 1 es: 8 21 b) d) 21 8
3) El largo de la curva \( x=\frac{y^{4}}{16}+\frac{1}{2 y^{2}} \) desde \( y=-2 \) hasta \( y=-1 \) es: a) \( \frac{16}{21} \) b) \( \frac{8}{21} \) c) \( \frac{21}{16} \) d) \( \frac{21}{8} \)2 answers -
question 9
1-12 = Use Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. 1. \( f(x, y)=x^{2}+y^{2} ; \quad x y=1 \) 2. \( f(x, y)=3 x+y ; \quad x^{2}+y^{2 answers -
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