Statistics And Probability Archive: Questions from December 02, 2022
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2 answers
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Determinar \( P(t \leq 1.54)=\quad \) para \( \mathrm{n}=46 \) A. \( 0.0863 \) B. \( 0.9347 \) C. \( 0.9434 \) D. \( 0.0014 \)2 answers -
verify that \[ E\left[J \sum_{i=1}^{I}\left(\bar{Y}_{i .}-\bar{Y}_{. .}\right)^{2}\right]=(I-1) \sigma^{2}+J \sum_{i=1}^{I} \alpha_{i}^{2} \]0 answers -
Determinar \( P(t \leq 0)= \) para \( \mathrm{n}=16 \) A. \( 0.5 \) B. \( 0.9870 \) C. \( 0.9434 \) D. \( 0.0014 \)1 answer -
2 answers
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2 answers
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2 answers
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3 answers
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2 answers
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Determinar \( P(t>1.54)=\quad \) para \( \mathrm{n}=46 \) A. \( 0.0863 \) B. \( 0.9347 \) C. \( 0.0653 \) D. \( 0.0014 \)2 answers -
Determinar \( P(t>0)=\quad \) para \( \mathrm{n}=16 \) A. \( 0.5 \) B. \( 0.9870 \) C. \( 0.9434 \) D. \( 0.0014 \)1 answer -
Determinar \( P(t \leq-3.56)=\quad \) para \( \mathrm{n}=16 \) A. \( 0.9694 \) B. \( 0.9870 \) C. \( 0.9434 \) D. \( 0.0014 \)2 answers -
Determinar \( P(t \leq-2.13)=\quad \) para \( n=24 \) A. \( 0.0220 \) B. \( 0.9870 \) C. \( 0.9434 \) D. \( 0.0014 \)2 answers