Other Math Archive: Questions from May 01, 2023
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Solve the given initial value problem \[ (D-1)\left(D^{2}+1\right)[y]=0, \quad y(0)=0, y^{\prime}(0)=2, y^{\prime \prime}(0)=2 \]2 answers -
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1. Solve \( y_{1}^{\prime}=y_{1}, y_{2}^{\prime}=y_{1}+y_{2}, \quad y_{1}(0)=1, y_{2}(0)=1 \) 2. Solve \( y^{\prime}=x, x^{\prime}=x+y, x(0)=1, y(0)=2 \)2 answers -
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Solve \( y_{1}^{\prime}=y_{1}, y_{2}^{\prime}=y_{1}+y_{2}, \quad y_{1}(0)=1, y_{2}(0)=1 \) Solve \( y^{\prime}=x, x^{\prime}=x+y, x(0)=1, y(0)=2 \)2 answers -
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\( \begin{array}{l}p=14 x+10 y+12 z \\ x+y-z \leq 3 \\ x+2 y+z \leq 8 \\ x+y \leq 5 \\ x \geq 0, y \geq 0, z \geq 0 \\\end{array} \)1 answer -
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\( y=\ln \left[x^{3} \cdot(8 x-19)^{4}\right] \) tion 4.5 \[ \begin{array}{l} y^{\prime}=\frac{64 x-36}{x(8 x-19)} \\ y^{\prime}=\frac{56 x-57}{x(8 x-19)} \\ y^{\prime}=\frac{42 x-31}{3 x(8 x-19)} \\2 answers -
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