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Computer Science Archive: Questions from December 11, 2022

• Find de equation sum of product and product of sum for each circuit.
  La tabla de verdad de salida múltiple es: \( F a_{(\text {sop })}= \) \( F a_{(p o s)}= \) La tabla de verdad de salida múltiple es: \( F_{\left.b_{(s o p}\right)}= \) \( F_{b_{(p o s)}}= \) La ta
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• Programa en codigo de Java:
  Un banco cobra \( \$ 10 \) por mes más las siguientes tarifas de cheques para una cuenta de cheques comercial: \( \$ .10 \) por cada cheque si se escribieron menos de 20 cheques \( \$ .08 \) por cada
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  ¿Proceso en que coteja los componentes al iniciar la computadora? POST CMOS BIOS EPROM
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  ¿Seleccione la ventaja de un sistema operativo de 64 -bit a 32-bit? Habilidad de usar software basado en Data Execution Prevention (DEP). Habilidad de instalar "unsigned driver Habilidad acceso a mas
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  ¿Proceso en que coteja los componentes al iniciar la computadora? POST CMOS BIOS EPROM
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• estimate the integral ∫−5.4−8f(x)dx using the best combination of the trapezoidal rules, Simpson 1/3 and Simpson 3/8. In case of four or more consecutive intervals of the same size, apply Simpso
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• We have to ∫100602x5+2exdx=204.396748350995. Complete the following table with the approximations to the integral given by the multiple application of the trapezoidal rule with n intervals. The last
  (1 point) Tenemos que \[ \int_{0}^{10} \frac{602 x}{5+2 e^{x}} d x=204.396748350995 . \] Completa la siguiente tabla con las aproximaciones a la integral dadas por la aplicaciẫn mÃ̃oltiple de la r
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• (1 point) Estimate the integral ∫120f(x)dx using the multiple trapezoidal rule and the following table x= 0 0.8 1.6 2.4 3.2 4 4.8 5.6 6.4 7.2 8 8.8 9.6 10.4 11.2 12 f(x)= 1.6 2.4 3.1 4.1 4.1 6.5 7.
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• (1 point) There is no closed form for the solution of the error function, erf(a)=2π−−√∫a0e−x2dx . Use the Trapezoidal Rule of multiple application by dividing the interval [0,0.9] into n=4
  (1 point) No existe forma cerrada para la solución de la función de error, \[ \operatorname{erf}(a)=\frac{2}{\sqrt{\pi}} \int_{0}^{a} e^{-x^{2}} d x \] Emplee la Regla del Trapecio de aplicación m�
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• If the Simple Trapezoid Rule is used to approximate ∫85sin(3x2)4xdx it is obtained that the integral is approximately: Note: Remember to calculate the trigonometric functions in radian mode. ​�
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• The estimate of the integral ∫−4−8(tan−1(2x−16)+π)dx with Simpson's rule 1/3 is . The true error of this approximation is Et= and the absolute relative error is |ϵt|= %. Formula: ∫ta
  (1 point) La estimación de la integral \[ \int_{-8}^{-4}\left(\tan ^{-1}\left(\frac{2 x-1}{6}\right)+\pi\right) d x \] con la regla de Simpson \( 1 / 3 \) es El error verdadero de esta aproximación
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• We wish to analyze the accuracy of different integration schemes. For this purpose, we will analyze the result of the definite integral ∫ln(4)0xexdx. (i) Using integration by parts, find the exact
  (1 point) Deseamos analizar la precisión de diferentes esquemas de integración. Para tal fin, analizaremos el resultado de la integral definida \[ \int_{0}^{\ln (4)} x e^{x} d x . \] (i) Usando inte
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• If the graph of a function f(x) continues on the interval [a,b] rotates about the x-axis it generates a surface S. It can be shown that the area A of S is given by: A=2π∫baf(x)1+(f′(x))2−−�
  (1 point) Si la grãjfica de una funciÃ̃ \( { }^{3} \mathrm{n} f(x) \) continua en el intervalo \( [a, b] \) gira alrededor del eje \( x \) genera una superficie \( S \). Se puede demostrar que el �
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• The work produced by a thermodynamic process at constant temperature, pressure and volume, is calculated by means of W=∫pdV where W is work, p is pressure, and V is volume. Considering that the fol
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• The error function is defined by erf(t)=2π−−√∫t0e−x2dx . This integral cannot be calculated analytically. (i) Consider the integrand as f(x)=e−x2, and complete the following table by e
  (1 point) La función error queda definida por \[ \operatorname{erf}(t)=\frac{2}{\sqrt{\pi}} \int_{0}^{t} e^{-x^{2}} d x \] Esta integral no puede calcularse de manera analítica. (i) Consideremos al
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• The total mass of a bar of variable density is given by m=∫L0ρ(x)A(x)dx . where m= mass, ρ(x)= density, A(x)= cross-sectional area, x=distance along the bar, and L= total length of the bar. The f
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• The angular velocity ( rad/s ) of an object that follows a circular path is given by the function v(t)=4π−−√cos(cos(6t)) . Therefore the position of the object (in radians) at time t is given
  (1 point) La velocidad angular \( (\mathrm{rad} / \mathrm{s}) \) de un objeto que sigue una trayectoria circular están dada por la función \[ v(t)=\sqrt{4 \pi} \cos (\cos (6 t)) \] Por lo tanto la p
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