Calculus Archive: Questions from March 21, 2023
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Find the Limit !!
\( \lim _{\substack{(x, y) \rightarrow(9,4) \\ y \neq 4}} \frac{x y+4 y-4 x-16}{y-4} \)2 answers -
Find the limit. 2) \( \lim _{(x, y) \rightarrow(4,5)}\left(\frac{4}{x}-\frac{2}{y}\right) \) 3) \( \lim _{(x, y) \rightarrow(9,4)} \frac{x y+4 y-4 x-16}{y-4} \)2 answers -
can anyone help me solve problem#11?
Calculating First-order Partial Derivatives In Exercises 1-22, find \( \partial f / \partial x \) and \( \partial f / \partial y \). 1. \( f(x, y)=2 x^{2}-3 y-4 \) 2. \( f(x, y \) 3. \( f(x, y)=\left(2 answers -
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\( \begin{array}{l}\frac{d}{d x}\left(\int_{\ln \left(x^{2}+1\right)}^{x^{2}} \frac{\cos (2 y)}{\sqrt[3]{y^{4}+\cos (3 y)+3}} d y\right) \\ \ln (t)=\log _{e}(t)\end{array} \)2 answers -
\( \begin{array}{l}\text { Find } \frac{d^{2} y}{d x^{2}} \\ \qquad y=5 x+8\end{array} \) \( \frac{d^{2} y}{d x^{2}}=5 \)2 answers -
Question 7 Find the indefinite integral. \[ \int \sin ^{3}(3 \theta) \cdot \sqrt{\cos (3 \theta)} \mathrm{d} \theta \] \[ \begin{array}{l} \frac{2}{9}(\cos (3 \theta))^{\frac{3}{2}}-\frac{2}{21}(\cos2 answers -
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(1 point) Find \( y \) as a function of \( x \) if \[ y^{\prime \prime \prime}-8 y^{\prime \prime}+12 y^{\prime}=5 e^{x} \] \[ y(0)=13, \quad y^{\prime}(0)=25, \quad y^{\prime \prime}(0)=29 \]2 answers -
(1 point) Find \( y \) as a function of \( x \) if \[ y^{\prime \prime \prime}-9 y^{\prime \prime}-y^{\prime}+9 y=0 \] \[ \begin{array}{l} y(0)--4 \quad v^{\prime}(n)--2 \quad v^{\prime \prime}(\cap)-2 answers -
(1 point) Find \( y \) as a function of \( x \) if \[ y^{\prime \prime \prime}-9 y^{\prime \prime}-y^{\prime}+9 y=0 \] \[ y(0)=0, \quad y^{\prime}(0)=3, \quad y^{\prime \prime}(0)=0 \text {. } \] \[ y2 answers -
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1. Hallar las derivadas parciales de: a. \( f(x, y)=y^{3}-4 x^{2} y-x \) b. \( g(x, y)=e^{2 y} \sin (x y) \) c. \( h(x, y, z)=\sin (2 x+y+4 z) \)2 answers -
2. Evaluar las derivadas parciales de cada función en el punto dado: a. \( f(x, y)=\frac{x y}{x-y} \) en el punto \( (2,-2) \). b. \( g(x, y)=\frac{6 x y}{\sqrt{4 x^{2}+5 y^{2}}} \) en el punto \( (12 answers -
4. Para cada función hallar los valores de \( x \) y los de \( y \) tales que \( \frac{\partial f}{\partial x}(x, y)=0 \) y \( \frac{\partial f}{\partial y}(x, y)=0 \) a. \( f(x, y)=x^{2}+4 x y+y^{2}2 answers -
Usando la regla de la cadena hallar \( \frac{\partial W}{\partial s} \) y \( \frac{\partial W}{\partial t} \) a. \( W=x \cos (y z), \quad x=s^{2}, \quad y=t^{2}, \quad z=s-2 t \) b. \( W=z e^{\frac{x}0 answers -
6. Considere la función \( W=f(x, y) \), donde \( x=u-v, \quad y=v-u \). Verificar que \( \frac{\partial W}{\partial u}+\frac{\partial W}{\partial v}=0 \).2 answers -
6. Considere la función \( W=f(x, y) \), donde \( x=u-v, \quad y=v-u \). Verificar que \( \frac{\partial W}{\partial u}+\frac{\partial W}{\partial v}=0 \).2 answers -
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Solve the initial value problems. a) \( y^{\prime \prime}+y^{\prime}=x \), and \( y(0)=1, y^{\prime}(0)=0 \) b) \( y^{\prime \prime}+y=8 \cos 2 x-4 \sin x, y(\pi / 2)=-1, y^{\prime}(\pi / 2)=-0 \)2 answers -
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Evaluate the double integral. \[ \iint_{D} 4 x \sqrt{y^{2}-x^{2}} d A, D=\{(x, y) \mid 0 \leq y \leq 3,0 \leq x \leq y\} \]2 answers -
Calculate the double integral. \[ \iint_{R} \frac{8\left(1+x^{2}\right)}{1+y^{2}} d A, R=\{(x, y) \mid 0 \leq x \leq 1,0 \leq y \leq 1\} \]2 answers -
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1.Determine the lenght of the arc in the given Interval. 2. Determine and interpret the curvature K of the curve at the value of the given parameter.
I. Determine la longitud del arco en el intervalo dado a) \( r(t)=i+t^{2} j+t^{3} k ;[0,2] \) b) \( r(t)=\langle 4 t,-\cos t, \operatorname{sen} t\rangle ;\left[0, \frac{3 \pi}{2}\right] \) II. Determ2 answers -
Find partial derivatives
1. Hallar las derivadas parciales de: a. \( f(x, y)=y^{3}-4 x^{2} y-x \) b. \( g(x, y)=e^{2 y} \sin (x y) \) c. \( h(x, y, z)=\sin (2 x+y+4 z) \)2 answers -
Find partial derivatives in a point given
2. Evaluar las derivadas parciales de cada función en el punto dado: a. \( f(x, y)=\frac{x y}{x-y} \) en el punto \( (2,-2) \). b. \( g(x, y)=\frac{6 x y}{\sqrt{4 x^{2}+5 y^{2}}} \) en el punto \( (12 answers -
3. Hallar \( \frac{\partial}{\partial x}\left(\frac{\partial f}{\partial x}\right)=\frac{\partial^{2} f}{\partial x^{2}}, \quad \frac{\partial}{\partial y}\left(\frac{\partial f}{\partial y}\right)=\f2 answers -
4. Para cada función hallar los valores de \( x \) y los de \( y \) tales que \( \frac{\partial f}{\partial x}(x, y)=0 \) y \( \frac{\partial f}{\partial y}(x, y)=0 \) a. \( f(x, y)=x^{2}+4 x y+y^{2}2 answers -
Using the chain rule, solve:
Usando la regla de la cadena hallar \( \frac{\partial W}{\partial s} \) y \( \frac{\partial W}{\partial t} \) a. \( W=x \cos (y z), \quad x=s^{2}, \quad y=t^{2}, \quad z=s-2 t \) b. \( W=z e^{\frac{x}2 answers -
Considere la función \( W=f(x, y) \), donde \( x=u-v, \quad y=v-u \). Verificar que \( \frac{\partial W}{\partial u}+\frac{\partial W}{\partial v}=0 \).2 answers -
Find the differential df. \[ f(x, y)=x \cos (y)-2 y \cos (x) \] a) \( \bigcirc \) df \( =(-x \sin (y)-2 \cos (x)) \Delta x+(\cos (y)+2 y \sin (x)) \Delta y \) b) \( \mathrm{df}=(\cos (y)+2 y \sin (x))2 answers -
Find the differential df. \[ f(x, y)=\ln \left(2 x^{2}+2 y^{2}\right)+3 x \mathrm{e}^{x y} \] a) \( \bigcirc \mathrm{df}=\left(4 \frac{x}{2 x^{2}+2 y^{2}}+3 \mathrm{e}^{x y}+3 x y \mathrm{e}^{x y}\rig2 answers -
Find the indicated partial derivatives. \[ f(x, y)=x^{8}+2 x y^{2}-4 y ; \frac{\partial^{2} f}{\partial x^{2}} ; \frac{\partial^{2} f}{\partial y^{2}} ; \frac{\partial^{2} f}{\partial x y} \] A. \[ \b2 answers -
the triple integral \( \iiint_{B} f(x, y, z) d V \) over the solid \( B \) \[ f(x, y, z)=1-\sqrt{x^{2}+y^{2}+z^{2}}, B=\left\{(x, y, z) \mid x^{2}+y^{2}+z^{2} \leq 25, y \geq 0, z \geq 0\right\} \]2 answers -
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Find the following. \[ \begin{array}{l} \int\left(x^{3}+y^{4}\right) d x= \\ \int\left(x^{3}+y^{4}\right) d y= \end{array} \]2 answers -
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Evaluate the integral \( \iint_{R}\left(\frac{x}{y}-\frac{y}{x}\right) d A \) over the rectangular region, \[ R=\{(x, y) \mid 1 \leq x \leq 2,1 \leq y \leq 5\} \] \[ \iint_{R}\left(\frac{x}{y}-\frac{y2 answers -
\[ \begin{array}{l} F_{1}(x, y)=x \mathbf{i}+\mathbf{y j} ; \quad F_{2}(\mathbf{x}, \mathbf{y})=-\mathbf{y i}+\mathbf{x} \mathbf{j} \\ F_{3}(x, y)=\frac{1}{\sqrt{x^{2}+y^{2}}}(x \mathbf{i}+\mathbf{y}0 answers -
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\[ \begin{array}{l} F_{1}(x, y)=x \mathbf{i}+\mathbf{y} \mathbf{j} ; \quad \mathbf{F}_{2}(\mathbf{x}, \mathbf{y})=-\mathbf{y} \mathbf{i}+\mathbf{x} \mathbf{j} ; \\ F_{3}(x, y)=\frac{1}{\sqrt{x^{2}+y^{0 answers -
Compute \( \iiint_{R}(x+y+2 z) d V \) over the box \( B= \) \( \{(x, y, z): 0 \leq x \leq 1,0 \leq y \leq 1, \quad 0 \leq z \leq 2\} \). 2 4 6 12 13 14 26 28 322 answers -
Find the differential df. \[ f(x, y)=4 x \cos (y)-3 y \cos (x) \] a) \( \quad \mathrm{df}=(4 \cos (y)+3 y \sin (x)) \Delta x+(4 x \sin (y)+3 \cos (x)) \Delta y \) b) \( \mathrm{df}=(-4 x \sin (y)-3 \c2 answers -
Find the differential df. \[ f(x, y)=\ln \left(x^{2}+4 y^{2}\right)+3 x \mathrm{e}^{x y} \] a) \( \bigcirc \mathrm{df}=\left(2 \frac{x}{x^{2}+4 y^{2}}+3 \mathrm{e}^{x y}+3 x y \mathrm{e}^{x y}\right)2 answers -
help with c and d
Prove the following identities. a) \( \frac{\cos x}{\sec x}+\frac{\sin x}{\csc x}=1 \) b) \( \csc x-\sin x=\cos x \cot x \) c) \( \sec t \csc t(\tan t+\cot t)=\sec ^{2} t+\csc ^{2} t \) d) \( (\tan y+2 answers -
valuate the triple integral \( \iiint_{E} f(x, y, z) d V \) over the solid \( E \). \[ f(x, y, z)=e^{\sqrt{x^{2}+y^{2}}}, E=\left\{(x, y, z) \mid 1 \leq x^{2}+y^{2} \leq 16, y \leq 0, x \leq y \sqrt{32 answers -
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need help with part b
Find each limit. \[ f(x, y)=\sqrt{y}(y+4) \] (a) \( \lim _{\Delta x \rightarrow 0} \frac{f(x+\Delta x, y)-f(x, y)}{\Delta x} \) (b) \( \lim _{\Delta y \rightarrow 0} \frac{f(x, y+\Delta y)-f(x, y)}{\D2 answers -
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Find the Vector addition of A + B + C and find the magnitude and direction of the resultant vector OF THAT ADDITION
Resuelva: Utilizando la siguente grảica de vectores en el plano cartesiano: Encuentra la suma vectorial \( \vec{A}+\vec{B}+\vec{C} \) y encuentre la magnitud y dirección del vector resultante de es2 answers -
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