Algebra Archive: Questions from August 03, 2023
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Find the derivative y = √√x³+7x² + 6x a. 1 y' = = (5x++ 14x+6)-¹/2 - 2 O b. 1 y'= == (x³ + 7x² + 6x) −¹/² (5x++ 14x + 6) 2 O c. 1 y '= = (x³ + 7x² + 6x) -1/2 2 O d. 1 'y' = = (x³ + 7xÂ
Find the derivative \[ y=\sqrt{x^{5}+7 x^{2}+6 x} \] \( y^{\prime}=\frac{1}{2}\left(5 x^{4}+14 x+6\right)^{-1 / 2} \) \( y^{\prime}=\frac{1}{2}\left(x^{5}+7 x^{2}+6 x\right)^{-1 / 2}\left(5 x^{4}+14 x2 answers