Advanced Math Archive: Questions from February 13, 2023
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2 answers
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Solve for the initial value problem
\( y^{\prime \prime}+y^{\prime}+4 y=0, \quad y(0)=1, \quad y^{\prime}(0)=-1 \)2 answers -
Find \( f(a) \) if \( f(t)=t^{2}-2 t-2 \) \( \mathbf{F}(t+a)^{2}-2 t+a-2 \) H \( a^{2}-2 t-2 \) \( \mathbf{G}(t+a)^{2}-2(t+a)-2 \) \( \mathbf{J} a^{2}-2 a-2 \)2 answers -
2 answers
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If \( \theta=\frac{\pi}{3} \), then \[ \cos \left(30^{\circ}\right)= \] \[ \sin \left(45^{\circ}\right)= \] \[ \cos \left(60^{\circ}\right)= \] \[ \sin \left(60^{\circ}\right)= \] \[ \cos \left(45^{\c2 answers -
In each of Problems 1 through 8 , solve the given differential equation. 1. \( y^{\prime}=\frac{x^{2}}{y} \) 2. \( y^{\prime}+y 2 \sin x=0 \) 3. \( y^{\prime}=\cos ^{2}(x) \cos ^{2}(2 y) \) 4. \( x y^2 answers -
\( \begin{array}{l}\lim _{x \rightarrow 1} f(x) \\ \lim _{x \rightarrow 3} f(x)\end{array} \) \( \begin{array}{l}\lim _{x \rightarrow-2} h(x) \\ \lim _{x \rightarrow 0} h(x)\end{array} \)2 answers -
2 answers
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1. (5 points) Solve the initial value problem \[ y^{\prime \prime}+y^{\prime}+4 y=0, \quad y(0)=1, \quad y^{\prime}(0)=-1 \]2 answers -
Los parametros son a=2, b=4, c=3. Gracias.
Resolver este problema de valor inicial usando el método de solución de ecuaciones homogéneas de primer orden, según discutido en clase. Escribir la respuesta en la forma \( y=f(x) \) completament2 answers -
Los parametros son a=2, b=4, c=3. Gracias.
Resolver este problema de valor inicial usando el método de solución de Reducción a Separable Escribir la respuesta en la forma \( y=f(x) \) completamente simplificada. \[ \frac{d y}{d x}=-a+2 \sqr2 answers -
1 answer
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Obtain a family of solutions for #16.
16. \( [x-y \ln (y)+y \ln (x)] d x+x[\ln (y)-\ln (x)] d y=0 \) 17. \( \left[x-y \tan ^{-1}\left(\frac{y}{x}\right)\right] d x+x \tan ^{-1}\left(\frac{y}{x}\right) d y=0 \)2 answers -
please help with 2,6,12
1-14. Solve each of the following differential equations using the Laplace transform method. Determine both \( Y(s)=\mathcal{L}\{y(t)\} \) and the solution \( y(t) \). 1. \( y^{\prime}-4 y=0, \quad y(2 answers -
Solving Initial Value Problems
16. \( y^{\prime}=-\frac{2 y}{x+1}+2 x, y(0)=2 \) \[ \begin{array}{l} \text { Hint. } y= \\ \frac{3 x^{4}+8 x^{3}+6 x^{2}+12}{6(x+1)^{2}} \end{array} \]2 answers