Advanced Math Archive: Questions from September 24, 2022
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If \( y^{\prime \prime}=\frac{1}{(x+1)^{2}}, y(0)=2, y^{\prime}(0)=1^{\text {then }} y^{\prime}= \) and \( y= \)2 answers -
If \( y=A x \cos (\ln x)+B x \sin (\ln x) \), then \( y^{\prime}= \) , \( y^{\prime \prime}= \) , Hence, \[ x^{2} y^{\prime \prime}-x y^{\prime}+2 y= \]2 answers -
If \( y=A x \cos (\ln x)+B x \sin (\ln x) \), then \( y^{\prime}= \) , \( y^{\prime \prime}= \) , Hence, \[ x^{2} y^{\prime \prime}-x y^{\prime}+2 y= \]1 answer -
Question 4 \[ \text { If } y^{\prime \prime}=\frac{1}{(x+1)^{2}}, y(0)=2 \cdot y^{\prime}(0)=1 \text { then } y^{\prime}=\quad \text { and } y= \]1 answer -
1 answer
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2 answers
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Use method Gauss Jordan
Resuelva los siguientes sistemas de ecuaciones lineales, utilizando el método de eliminación de Gauss - Jordan: 1. \( 3 x-2 y+4 z=1 \) \[ \begin{array}{c} x+y-2 x=3 \\ 2 x-3 y+6 z=8 \end{array} \] 22 answers -
Halle la inversa, si existe, de cada una de las siguientes matrices \( A \), utilizando la matriz escalonada reducida con operaciones elementales fila de la matriz (AI) 4. \( \left(\begin{array}{lll}11 answer -
(e),thanks
Find the solution of the following initial value problem. (a) \( 4 y^{\prime \prime}-y=0, \quad y(-2)=1, \quad y^{\prime}(-2)=-1 \) (b) \( y^{\prime \prime}-4 y^{\prime}+3 y=0, \quad y(0)=2, \quad y^{1 answer -
\( \int(2 a y) \operatorname{Ln}\left(-a+\sqrt{A+y^{2}}\right) d y \) \( \{a, A, y\} \in \mathbb{R} \wedge\left(-a+\sqrt{A+y^{2}}\right)> \)1 answer