Using spherical coordinates evaluates ∭ (𝑥 2 + 𝑦 2 + 𝑧 two )𝑑𝑉 𝐸 where E is the solid between the two spheres 𝑥 2 + 𝑦 2 + 𝑧 2 = 1 y𝑥 2 + 𝑦 2 + 𝑧 2 = 4

The given integral is intintint_E(x^2+y^2+z^2)dV Where E is the solid between x^2+y^2+z^2=1and x^2+y^2+z^2=4 In spherical coordinate system

Resuelto Using spherical coordinates evaluates ∭ (𝑥 2 + 𝑦 2

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Pregunta: Using spherical coordinates evaluates ∭ (𝑥 2 + 𝑦 2 + 𝑧 two )𝑑𝑉 𝐸 where E is the solid between the two spheres 𝑥 2 + 𝑦 2 + 𝑧 2 = 1 y𝑥 2 + 𝑦 2 + 𝑧 2 = 4

Using spherical coordinates evaluates ∭ (𝑥 2 + 𝑦 2 + 𝑧 two )𝑑𝑉 𝐸 where E is the solid between the two spheres 𝑥 2 + 𝑦 2 + 𝑧 2 = 1 y𝑥 2 + 𝑦 2 + 𝑧 2 = 4

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Paso 1
The given integral is $\int \int \int_{E} (x^{2} + y^{2} + z^{2}) d V$
Where $E$ is the solid between $x^{2} + y^{2} + z^{2} = 1 and x^{2} + y^{2} + z^{2} = 4$

In spherical coordinate system
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Texto de la transcripción de la imagen:

X. Usando coordenadas esféricas evalúa

∭_{E} (x^{2} + y^{2} + z^{2}) d V

donde

E

es el sólido entre las dos esferas

x^{2} + y^{2} + z^{2} = 1

x^{2} + y^{2} + z^{2} = 4