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Mira la respuestaMira la respuesta done loading Muestra el texto de la transcripción de la imagenPregunta: Un bibliotecario considera que el tiempo entre alquileres de libros en hora pico sigue una distribución Exponencial con media 14 minutos. Para verificarlo, él tomó una muestra aleatoria de 140 datos y los organizó en la tabla que aparece a continuación: Con un nivel se significancia de α=0.025, si se realiza una prueba de Bondad de Ajuste Chi Cuadrado con
Translation:
A librarian considers that the time between book rentals during peak hours follows an Exponential distribution with a u= 14 minutes. To verify this, he took a random sample of 140 data points and organized them into the table below:
With a significance level of alpha=0.025, if a Chi Square Goodness of Fit test is performed with the data described, it can be concluded that:
Options:
A) The hypothesis that the times between rentals follow an Exponential distribution with a mean of 14 minutes cannot be rejected, since the p-value is 0.2402.
B)The hypothesis that the times between rentals follow an Exponential distribution with a mean of 14 minutes cannot be rejected, since the p-value corresponding to the calculated Test Statistic is 0.75982.
C)The hypothesis that the data follow an Exponential distribution with a mean of 14 minutes is rejected, since the Calculated Test Statistic is 56.31.
D)The hypothesis that the times between rentals follow an Exponential distribution with a mean of 14 minutes cannot be rejected, since the calculated Test Statistic is 0.4022.
E) The hypothesis that the data follow an Exponential distribution with a mean of 14 minutes is rejected, since the Calculated Test Statistic is 1.17.
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The given data is:
Time
Observed Frequency (O)
Less than 10 minutes
67
Between 10 and 25 minutes
51
Between 25 and 45 minutes
17
45 minutes or more
5
Total
140
Let X be the random variable which denotes the time between book rentals during pe...
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