A proton enters a region where the electric field has a magnitude of 6700 N/C oriented to the right. If the initial speed of the electron is 2.5 x 104 m/s, calculate the speed after it has traveled 2.0 cm in the electric field.a) 160 x 103m/sb) 6.4 x 1011 m/sc) 2.6 x 1010 m/sd) 1.6 x 106 m/s

proton enters a region where the electric field has a magnitude of E=6700N/C Oriented to right. Charge of pro...

Resuelto A proton enters a region where the electric field has

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eléctrico a.

160 \times 1 0^{3} m / s

6.4 \times 1 0^{11} m / s

2.6 \times 1 0^{10} m / s

1.6 \times 1 0^{6} m / s