Paste
Copy
Cut
Options

¡Tu solución está lista!

Nuestra ayuda de expertos desglosó tu problema en una solución confiable y fácil de entender.

Mira la respuesta

  • Pregunta: In Problems 31 through 42, verify that the given differential equation is exact: then solve it. (2x + 3y) dx + (3x + 2y) dy = 0 (4x - y) dx + (6y - x) dy = 0 (3x^2 + 2y^2) dx + (4xy + 6y^2) dy = 0 (2xy^2 + 3x^2) dx + (2x^2y + 4y^3) dy = 0 (x^3 + y/x) dx + (y^2 + ln x) dy = 0 (1 + ye^xy) dx + (2y + xe^xy) dy = 0 (cos x + ln y) dx + (x/y + e^y) dy = 0

    complete #32 and #36
    student submitted image, transcription available below
    Muestra el texto de la transcripción de la imagen
  • Chegg Logo
    Hay 2 pasos para resolver este problema.
    Solución
    Paso 1

    Given that the differential equations

    32)(4x−y)dx+(6y−x)dy=0

    Comparing it with Mdx+Ndy=0

    Mira la respuesta completa
    answer image blur
    Paso 2
    Desbloquea
    Respuesta
    Desbloquea
Texto de la transcripción de la imagen:
In Problems 31 through 42, verify that the given differential equation is exact: then solve it. (2x + 3y) dx + (3x + 2y) dy = 0 (4x - y) dx + (6y - x) dy = 0 (3x^2 + 2y^2) dx + (4xy + 6y^2) dy = 0 (2xy^2 + 3x^2) dx + (2x^2y + 4y^3) dy = 0 (x^3 + y/x) dx + (y^2 + ln x) dy = 0 (1 + ye^xy) dx + (2y + xe^xy) dy = 0 (cos x + ln y) dx + (x/y + e^y) dy = 0 (x + tan^-1 y) dx + x + y/1 + y^2 dy = 0 (3x^2y^3 + y^4) dx + (3x^3y^2 + y^4 + 4xy^3) dy = 0 (e^x sin y + tan y) dx + (e^x cos y + x sec^2 y) dy = 0 (2x/y - 3y^2/x^4) dx + (2y/x^3 - x^2/y^2 + 1/squareroot y)dy = 0 2x^5/2 - 3y^5/3/2x^5/2 y^2/3 dx + 3y^5/3 - 2x^5/2/3x^3/2 y^5/3 dy = 0