Precalculus Archive: Questions from July 22, 2023
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Verify the identity. \[ \begin{array}{l} \frac{7 \tan x+6 \tan y}{1-\tan x \tan y}=\frac{6 \cot x+7 \cot y}{\cot x \cot y-1} \\ \frac{7 \tan x+6 \tan y}{1-\tan x \tan y}=\frac{\frac{7}{\cot x}+\frac{62 answers -
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