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  • Pregunta: sinαsinβ+sinαsinβ tan(α−β)=sin(α−β)cos(α−β)=sinαcosβ+cosαsinβcosαcosβ−sinαsinβ=sinαsinβsinαcosβ+cosαsinβsinαsinβcosαcosβ−sinαsinβ =sinαsinβsinαcosβ+sinαsinβcosαsinβsinαsinβcosαcosβ−sinαsinβsinαsinβ=cotαcotβ+1cotβ−cotαsinαsinβ+sinαsinβ tan(α−β)=cos(α−β)sin(α−β)=cosαcosβ+sinαsinβsinαcosβ−cosαsinβ=cosαcosβcosαcosβ+sinαsinβcosαcosβsinαcosβ−cosαsinβ

    student submitted image, transcription available below

    student submitted image, transcription available below

    student submitted image, transcription available below

    Muestra el texto de la transcripción de la imagen
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    Queda solo un paso para resolver este problema.
    Solución
    Paso 1

    Given identity is

    tan(αβ)=cotβcotαcotαcotβ+1

    Now, L.H.S= tan(αβ)

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Texto de la transcripción de la imagen:
sinαsinβ+sinαsinβ tan(αβ)=sin(αβ)cos(αβ)=sinαcosβ+cosαsinβcosαcosβsinαsinβ=sinαsinβsinαcosβ+cosαsinβsinαsinβcosαcosβsinαsinβ =sinαsinβsinαcosβ+sinαsinβcosαsinβsinαsinβcosαcosβsinαsinβsinαsinβ=cotαcotβ+1cotβcotα sinαsinβ+sinαsinβ tan(αβ)=cos(αβ)sin(αβ)=cosαcosβ+sinαsinβsinαcosβcosαsinβ=cosαcosβcosαcosβ+sinαsinβcosαcosβsinαcosβcosαsinβ =cosαcosβcosαcosβ+cosαcosβsinαsinβcosαcosβsinαcosβcosαcosβcosαsinβ=cotαcotβ+1cotβcotα Establish the identity. tan(αβ)=cotαcotβ+1cotβcotα Choose the sequence of steps below that verifies the identity. A. tan(αβ)==cos(αβ)sin(αβ)=cosαcosβ+sinαsinβsinαcosβcosαsinβ=sinαsinβcosαcosβ+sinαsinβsinαsinβsinαcosβcosαsinβsinαsinβcosαcosβ+sinαsinβsinαsinβsinαsinβsinαcosβsinαsinβcosαsinβ=cotαcotβ+1cotβcotα