Other Math Archive: Questions from June 09, 2023
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The solution of the boundary value problem: \( y^{\prime \prime}+4 y=0, y(0)=1, y^{\prime}(\pi / 4)=0 \) is (i) \( y=\sin 2 x \) (ii) \( y=\cos 2 x \) (iii) \( y=\cos (4 x) \) (iv) \( y=\sin (4 x) \)2 answers -
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For the given function below. f(x, y) = 4x¹ + 4y¹ − 1024xy - (a) List all critical points. No decimal values.
For the given function below. \[ f(x, y)=4 x^{4}+4 y^{4}-1024 x y \] (a) List all critical points. No decimal values.2 answers -
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Solve
Solvel \( y^{\prime \prime}+5 y^{\prime}+4 y=0 \quad y(0)=y^{\prime}(0)=1 \) Solvel \( y^{\prime \prime}+4 y^{\prime}-2 y=0 \quad y(0)=1 \quad y^{\prime}(0)=-2 \)2 answers