Other Math Archive: Questions from September 09, 2022
-
Solve the following differential equations. (1) \( \left(2 x y^{3}-e^{x} \cos y\right) d x+\left(3 x^{2} y^{2}+e^{x} \sin y\right) d y=0 \) (2) \( \left(y+\frac{-2 y}{x^{2}-y^{2}}\right) d x+\left(x+\1 answer -
Yes a = [ 1 −2 2 ] , b = [ 3 −5 7 ] , c = [ −3 9 −2 ] , d = [ −5 8 −12 ] In determining the coefficients c1, c2 and c3 such that a) c 1 c + c two a + c 3 b = 0 A: Identify your conclusion
\[ \mathbf{a}=\left[\begin{array}{r} 1 \\ -2 \\ 2 \end{array}\right], \mathbf{b}=\left[\begin{array}{r} 3 \\ -5 \\ 7 \end{array}\right], \mathbf{c}=\left[\begin{array}{r} -3 \\ 9 \\ -2 \end{array}\rig1 answer -
For the linear transformation of R 4 it is R 4 defined as T [ x y z w ] = [ −12w−71x+y+z −4w−24x 17w+101x−y−z 72w+426x−6y−6z ] classify vectors a) [ 6 4 −11 −36 ] b) [ −6 −4 11
Para la transformación lineal de \( R^{4} \) en \( R^{4} \) definida como \[ T\left[\begin{array}{l} x \\ y \\ z \\ w \end{array}\right]=\left[\begin{array}{r} -12 w-71 x+y+z \\ -4 w-24 x \\ 17 w+1011 answer -
1 answer
-
Solve the initial value problem. \[ \frac{1}{\theta} \frac{d y}{d \theta}=\frac{y \cos \theta}{y^{3}+1}, y(0)=1 \]1 answer