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Mira la respuestaMira la respuesta done loading Muestra el texto de la transcripción de la imagenPregunta: Need Help. The image shows a multiple-choice question in Spanish about the use of Microarray technology in cancer research. The question is, "What is the Microarray technique used for in cancer?"The options provided are:To conduct large
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The image shows a multiple-choice question in Spanish about the use of Microarray technology in cancer research. The question is, "What is the Microarray technique used for in cancer?"
The options provided are:
- To conduct large genomic studies and analyze differences between normal and tumor cells and discriminate potential biomarkers.
- To compare different stages of a tumor and understand more about its genetic transformation.
- If biomarker primers are included, to timely identify the presence of cancer cells in patient samples.
- To design therapies knowing which genes are involved in cancer.
- To know the states of methylation, acetylation, and other PTMs (Post-Translational Modifications) in cancer.
The image shows a question in Spanish related to the role of DAG (diacylglycerol) in cancer signaling pathways. The question asks what DAG is in cancer signaling cascades.
The options provided are:
- A promoter of cancer in conjunction with other factors
- A cancer inhibitor by itself
- A tumor suppressor gene
- A ligand that participates in oxidative phosphorylation
- A promoter of apoptosis in conjunction with other factors when well regulated
The image displays a question in Spanish related to cancer biology, which translates to:
"A tumor that shows proliferation towards deep tissues but does not show the development of blood vessels explains:"
The possible answers are:
- All of the above
- That it does not have the potential to metastasize
- Because some tumors are hypoxic
- The difference between invasion and metastasis
- That it is necessary to plan effective treatment strategies
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The correct option is:
To conduct large genomic studies and analyze differences between normal and tu...
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