Pregunta: Find ∬D(4x+3y)dA where D={(x,y)∣x2+y2≤4,x≥0}

We have to find the integral, $\mathrm{I}=\int {\int }_{\mathrm{D}}(4\mathrm{x}+3\mathrm{y})\mathrm{d}\mathrm{A}$ , where $\mathrm{D}=\{(\mathrm{x},\mathrm{y})\mid {\mathrm{x}}^2+{\mathrm{y}}^2\le 4,\mathrm{x}\ge 0\}$

We can observe that $\mathrm{D}$ is the area inside the circle ${\mathrm{x}}^2+{\mathrm{y}}^2=4$ lying in ...