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  • Pregunta: Express the integral ∭Ef(x,y,z)dV as an iterated integral in six different ways, where E is the solid bounded by z=0,x=0,z=y−2x and y=8. 1. ∫ab∫g1(x)g2(x)∫h1(x,y)h2(x,y)f(x,y,z)dzdydxa=b=g1(x)=g2(x)=h1(x,y)=h2(x,y)= 2. ∫ab∫g1(y)g2(y)∫h1(x,y)h2(x,y)f(x,y,z)dzdxdya=b=g1(y)=g2(y)=h1(x,y)=h2(x,y)= 3.


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    Solución
    Paso 1

    Given the integral Ef(x,y,z)dV

    where E is the solid bounded by z=0,x=0,z=y2xandy=8 .


    1. abg1(x)g2(x)h1(x,y)h2(x,y)(x,y,z)dzdydx

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Texto de la transcripción de la imagen:
Express the integral Ef(x,y,z)dV as an iterated integral in six different ways, where E is the solid bounded by z=0,x=0,z=y2x and y=8.  1. abg1(x)g2(x)h1(x,y)h2(x,y)f(x,y,z)dzdydxa=b=g1(x)=g2(x)=h1(x,y)=h2(x,y)=  2. abg1(y)g2(y)h1(x,y)h2(x,y)f(x,y,z)dzdxdya=b=g1(y)=g2(y)=h1(x,y)=h2(x,y)=  3. abg1(z)g2(z)h1(y,z)h2(y,z)f(x,y,z)dxdydza=b=g1(z)=g2(z)=h1(y,z)=h2(y,z)= 4. abg1(y)g2(y)h1(y,z)h2(y,z)f(x,y,z)dxdzdya=b=g1(y)=g2(y)=h1(y,z)=h2(y,z)=  5. abg1(x)g2(x)h1(x,z)h2(x,z)f(x,y,z)dydzdxa=b=g1(x)=g2(x)=h1(x,z)=h2(x,z)=  6. abg1(z)g2(z)h1(x,z)h2(x,z)f(x,y,z)dydxdza=b=g1(z)=g2(z)=h1(x,z)=h2(x,z)=