Establish the identity. sinαcosβsin(α−β)=1−cotαtanβ Choose the sequence of steps below that verifies the identity. A. sinαcosβsin(α−β)=sinαcosβsinαcosβ−cosαsinβ=sinαcosβsinαcosβ−sinαcosβcosαsinβ=1−cotαtanβ B. sinαcosβsin(α−β)=cosαsinβsinαcosβ−cosαsinβ=cosαsinβsinαcosβ−cosαsinβcosαsinβ=1−cotαtanβ C.

Resuelto Establish the identity. sinαcosβsin(α−β)=1−cotαtanβ

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Pregunta: Establish the identity. sinαcosβsin(α−β)=1−cotαtanβ Choose the sequence of steps below that verifies the identity. A. sinαcosβsin(α−β)=sinαcosβsinαcosβ−cosαsinβ=sinαcosβsinαcosβ−sinαcosβcosαsinβ=1−cotαtanβ B. sinαcosβsin(α−β)=cosαsinβsinαcosβ−cosαsinβ=cosαsinβsinαcosβ−cosαsinβcosαsinβ=1−cotαtanβ C.

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Establish the identity.

\frac{s i n ( α - β )}{s i n α c o s β} = 1 - cot α tan β

Choose the sequence of steps below that verifies the identity. A.

\frac{s i n ( α - β )}{s i n α c o s β} = \frac{s i n α c o s β - c o s α s i n β}{s i n α c o s β} = \frac{s i n α c o s β}{s i n α c o s β} - \frac{c o s α s i n β}{s i n α c o s β} = 1 - cot α tan β

\frac{s i n ( α - β )}{s i n α c o s β} = \frac{s i n α c o s β - c o s α s i n β}{c o s α s i n β} = \frac{s i n α c o s β}{c o s α s i n β} - \frac{c o s α s i n β}{c o s α s i n β} = 1 - cot α tan β

\frac{s i n ( α - β )}{s i n α c o s β} = \frac{s i n α c o s β + c o s α s i n β}{s i n α c o s β} = \frac{s i n α c o s β}{s i n α c o s β} + \frac{c o s α s i n β}{s i n α c o s β} = 1 - cot α tan β

\frac{s i n ( α - β )}{s i n α c o s β} = \frac{c o s α c o s β - s i n α s i n β}{s i n α c o s β} = \frac{c o s α c o s β}{s i n α c o s β} - \frac{s i n α s i n β}{s i n α c o s β} = 1 - cot α tan β