Establish the identity. sinαsinβcos(α+β)=cotαcotβ−1 Choose the sequence of steps below that verifies the identity. A. sinαsinβcos(α+β)=sinαsinβsinαsinβ+cosαcosβ=sinαsinβsinαsinβ+sinαsinβcosαcosβ=cotαcotβ−1 B. sinαsinβcos(α+β)=cosαcosβcosαcosβ−sinαsinβ=cosαcosβcosαcosβ−cosαcosβsinαsinβ=cotαcotβ−1 C.

L.H.S=cos(alpha + beta)/sin(alpha)sin(beta)

Resuelto Establish the identity. sinαsinβcos(α+β)=cotαcotβ−1

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Pregunta: Establish the identity. sinαsinβcos(α+β)=cotαcotβ−1 Choose the sequence of steps below that verifies the identity. A. sinαsinβcos(α+β)=sinαsinβsinαsinβ+cosαcosβ=sinαsinβsinαsinβ+sinαsinβcosαcosβ=cotαcotβ−1 B. sinαsinβcos(α+β)=cosαcosβcosαcosβ−sinαsinβ=cosαcosβcosαcosβ−cosαcosβsinαsinβ=cotαcotβ−1 C.

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L.H.S=cos(alpha + beta)/sin(alpha)sin(beta)
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Texto de la transcripción de la imagen:

Establish the identity.

\frac{c o s ( α + β )}{s i n α s i n β} = cot α cot β - 1

Choose the sequence of steps below that verifies the identity. A.

\frac{c o s ( α + β )}{s i n α s i n β} = \frac{s i n α s i n β + c o s α c o s β}{s i n α s i n β} = \frac{s i n α s i n β}{s i n α s i n β} + \frac{c o s α c o s β}{s i n α s i n β} = cot α cot β - 1

\frac{c o s ( α + β )}{s i n α s i n β} = \frac{c o s α c o s β - s i n α s i n β}{c o s α c o s β} = \frac{c o s α c o s β}{c o s α c o s β} - \frac{s i n α s i n β}{c o s α c o s β} = cot α cot β - 1

\frac{c o s ( α + β )}{s i n α s i n β} = \frac{c o s α c o s β - s i n α s i n β}{s i n α s i n β} = \frac{c o s α c o s β}{s i n α s i n β} - \frac{s i n α s i n β}{s i n α s i n β} = cot α cot β - 1

\frac{c o s ( α + β )}{s i n α s i n β} = \frac{c o s α c o s β + s i n α s i n β}{s i n α s i n β} = \frac{c o s α c o s β}{s i n α s i n β} + \frac{s i n α s i n β}{s i n α s i n β} = cot α cot β - 1