Electrical Engineering Archive: Questions from October 12, 2022
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Solve the following IVPs using convolution. (You may leave your answer in the format \( f * g \). 1. \( y^{\prime \prime}-2 y^{\prime}+y=f(t), \quad y(0)=k_{0}, \quad y^{\prime}(0)=k_{1} \). (24 marks1 answer -
What is the electric potential at the center of the triangle in the figure? If q1 = 10 nC and q2 = q3 = 10.nC.
¿Cuál es el potencial eléctrico en el centro del triángulo de la figura? Si q1 \( =10 \mathrm{nC} \) y q2 \( =\mathrm{q} 3=10 . \mathrm{nC} \). De su respuesta a un lugar decimal.1 answer -
only number 2
Solve the following IVPs using convolution. (You may leave your answer in the format \( f * g \). 1. \( y^{\prime \prime}-2 y^{\prime}+y=f(t), \quad y(0)=k_{0}, \quad y^{\prime}(0)=k_{1} \). (24 marks1 answer -
The positioning control system of a robot has a digital controller given by the expression: The difference equation of the control algorithm is given by:
El sistema de control de posicionamiento de un robot tiene un controlador digital dado por la expresión: \[ G c(z)=\frac{U(z)}{M(z)}=\frac{K_{p}}{z^{2}+2 z+1} \] La ecuación de diferencias del algor2 answers -
Resultados Etapa 1: \( \quad \) Resultados Etapa 2: \( \quad \) Resultados Totales: \( \mathrm{I}_{\mathrm{E}}=\mathrm{l}_{\mathrm{E}}=\ldots \mathrm{R}= \) \( r_{e}^{\prime}=\quad r_{e}^{\prime}=\ldo1 answer