the ecuation of the tangent line to the graph of the function f(x)= x^2lnx on the point (1,0) is:

we have to find equation of the tangent to the curve y=x^2lnx at point (1,0) For this we first differentiate ...

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Pregunta: the ecuation of the tangent line to the graph of the function f(x)= x^2lnx on the point (1,0) is:
the ecuation of the tangent line to the graph of the function f(x)= x^2lnx on the point (1,0) is:

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Solución
Paso 1
we have to find equation of the tangent to the curve $y = x^{2} \ln x$ at point (1,0)
For this
we first differentiate ...
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Paso 2
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