Calculus Archive: Questions from January 05, 2023
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\[ \begin{array}{l} \left(\frac{1}{x}+2 x y^{2}\right) d x+\left(2 x^{2} y-\cos y\right) d y=0 \\ y(1=)+1, x>0 \end{array} \] Solve please2 answers -
2 answers
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\[ \frac{d y}{d x} \text { of } y=\left(3 x^{2}-2\right) \sin ^{2} x \] ct one: \[ \begin{array}{l} 6 x \sin ^{2} x+2\left(3 x^{2}-2\right) \sin x \\ 6 x \sin ^{2} x+\left(3 x^{2}-2\right) \sin x \cos2 answers -
Find \( a+b+c+d \) if \( \cos (3 x)+-3 \cos (2 x)=a\left(\cos ^{3} x\right)+b\left(\cos ^{2} x\right)+c(\cos x)+d \)2 answers