Calculus Archive: Questions from September 08, 2022
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Hello can you solve the 4th exercise?
4. Solve the initial value problem. (a) \( y^{\prime}=-x e^{x}, \quad y(0)=1 \) (b) \( y^{\prime}=x \sin x^{2}, \quad y\left(\sqrt{\frac{\pi}{2}}\right)=1 \) (c) \( y^{\prime}=\tan x, y(\pi / 4)=3 \)1 answer -
From the differential equations below select all the equations that are Euler Homogenous equations. \[ \begin{aligned} y^{\prime} &=1+\frac{y}{t}+\frac{t}{y} \\ y^{\prime} &=\frac{y^{2}+t y+t^{2}}{t y1 answer -
If \( f(x)=\int_{0}^{x} \sin (3-t) d t \), then \( f^{\prime}(x)= \) a. \( \sin (3-x) \) b. \( \cos (3-x) \) c. \( -\cos (3-x) \) d. \( x \sin (3-x) \)1 answer -
Consider w to determine dw
Considere \( w=x^{2}-2 x y+y^{2}, x=r+\theta, y=r-\theta \) para determinar \( \frac{\partial w}{\partial r} \& \frac{\partial w}{\partial \theta} \). 1. Considere \( w=x y \cos (z), x=t, y=t^{2} \& z2 answers -
esuelva \( 2 x^{2} y d x=\left(3 x^{3}+y^{3}\right) d y \) \[ y^{9}=c\left(x^{3}+y^{3}\right)^{2} \] \[ \frac{c}{y^{9}}=\left(x^{3}+y^{3}\right)^{2} \] \[ \frac{2}{3} \ln \left(x^{3}+y^{3}\right)^{2}=1 answer -
Exercise. Select all vertical asymptotes of \( g \) below. \begin{tabular}{|l|} \hline\( y=5 \) \\ \hline\( x=5 \) \\ \hline\( x=-5 \) \\ \hline\( x=16 \) \\ \hline\( y=16 \) \\ \hline\( x=4 \) \\ \hl0 answers -
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\[ f(x, y)=\sqrt[3]{9-3 x^{2}-y^{2}} \] a. El plano tangente en \( (1,2) \) es \( 1.4142135 \ldots-3(x-1)-2(x-2) \) b. El grafico de la funcion es una parte de un elipsoide c. \( z= \) El plano tangen0 answers -
\[ f(x, y)=\sqrt[3]{9-3 x^{2}-y^{2}} \] Dar la proximacion lineal de 1 en \( (1.1,19) \) (Dar al menos 3 decimales en la respuesta. Considerar el punto base como \( (x \) (Cy_0) =(1,2)) Respuesta:0 answers -
Describe the domain and range of the function. \[ f(x, y)=\arccos (x+y) \] Domain: \[ \begin{array}{l} \{(x, y): x+y \leq-1\} \\ \{(x, y):-1 \leq x+y \leq 1\} \\ \{(x, y): x+y \geq 1\} \\ \{(x, y):-11 answer -
\[ f(x, y)=\sqrt[2]{9-3 x^{2}-y^{2}} \] a. El plano tangente en \( (1,2) \) es \( 1.4142135 \ldots-3(x-1)-2(x-2) \) b. El grafico de la funcion es una parte de un elipsoide c. \( z= \) El plano tangen1 answer -
\[ f(x, y)=\sqrt[3]{9-3 x^{2}-y^{2}} \] Dar la provimacion lineal de f en \( (1: 1,1.9) \) (Dar al menos 3 decimales en la respoesta. Considerar el punto base como (x_0,y_0) \( =(t, 2) \) ) Respuesta:1 answer -
Ejercicios: I. Considere \( w=x^{2}-2 x y+y^{2}, x=r+\theta, y=r-\theta \) para determinar \( \frac{\partial w}{\partial r} \& \frac{\partial w}{\partial \theta} \). II. Considere \( w=x y \cos (z), x1 answer -
(1 point) Find \( \nabla f \) at the given point. \[ f(x, y, z)=9 z^{3}-2\left(x^{2}+y^{2}\right) z+\tan ^{-1}(4 x z),(0,4,7) \] \[ \left.\nabla f\right|_{(0,4,7)}= \] \[ f(x, y, z)=e^{x+y} \cos (8 z)2 answers -
7) \( g(z)=\frac{z^{2}}{z^{5}-3} \) 8) \( p(x)=\frac{(2 x-1)\left(4 x^{3}+3 x^{2}-2\right)}{x} \) Use formulas to differentiate (do not need limits). Use proper notation and simplify your final answe1 answer -
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explain the steps please
3.) Find the \( y^{\prime}=\frac{d y}{d x} \) if \( x^{2} y^{3}=2 x-y \) A) \( y^{\prime}=\frac{2\left(x^{2} y^{3}-1\right)}{1+3 x y^{2}} \) B) \( y^{\prime}=\frac{2\left(x y^{2}-1\right)}{2+3 x y^{2}1 answer -
help me
Determine el vector unitario en dirección de la fuerza P. \[ \mathrm{u}=( \] \( \mathbf{i}+ \) j + Utilice tres cifras significativas para sus resultados.1 answer -
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find all indefinite integrals
\( \int \frac{2 x^{3}+6 x^{2}+10 x-4}{2 x^{2}} d x \) \( \int\left(x^{2}-2 x\right)\left(x^{3}-3 x^{2}\right)^{-5} d x \) \( \int 8 \sin ^{2} \theta d \theta \)2 answers