Calculus Archive: Questions from June 18, 2022
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y"+y = g(t); 2 10. y"+y+ y = g(t); 2 11. y" +4y= U₂ (1) - Uz(t); y(0) = 0, y'(0) = 1; g(t) = y(0) = 0, y'(0) = 0; [1/2, 0≤11 answer -
1 answer
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If f(x)= e^x/x, then f^(1) (x)=
ex Si f(x) = entonces f(¹)(x) = X Seleccione una: e +1 O a. X O b. e-1 x² O c. ex (x-1) x² O d. ex1 answer -
Sketch the level curve z = k for the specified values of k. ■ 53. z = x² + y; k = -2, -1, 0, 1, 2 55. z = x² - y²; k= -2, -1, 0, 1, 2 Sketch the level surface f(x, y, z) = k. ■ 57. f(x, y, z) =3 answers -
1 answer
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Find the first partial derivatives of the function. f(x, y, z, t) = 6xyzº tan(yt) fx(x, y, z, t) = I fy(x, y, z, t) = f₂(x, y, z, t) = f(x, y, z, t): =1 answer -
Question 8 Evaluate the integral: f4 sin x O y = 4 cos x + c O y = -4 sin x + c O y = -4 cos x +C Oy = 4 sin x + c 8 pts1 answer -
Question 2 Match the equation with its derivative: y = x + sin 4x y = x + cos 4x y = x - sin 4x y = x - cos 4x [Choose ] [Choose ] y' = 1-4 sin 4x y' = 1 + 4 sin 4x y' = 1 + 4 cos 4x y' = 1-4 cos 4x [1 answer -
Question 3 Match the equation with its derivative: y = -3sin(л-x) y = 3сos(л-x) y = 3sin(л-x) y = -3cos(π-x) [Choose ] Choose ] y' = 3cos(TT-x) y = -3cos (TT-x) y' = 3sin(TT-x) y' = -3sin(TT-x) [1 answer -
Question 4 Find the derivative: sin a y= cos x O y tan z COS Oy sin O y =sec = O y = sec² x = cos 1 cos² a 7 pts1 answer