Calculus Archive: Questions from July 05, 2022
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1. Find the solution: (cos y) y' (t) = sin² tcost, y (0) = 2. Find the solution: y' (x) = e sinx, y (T) = ln 21 answer -
dy Use separation of variables to solve dx y = −(e² − 1) = / y = e(e²+1) y = 1- ex y = ln(1 + e*) = e* (1 — y)², given y(0) = 01 answer -
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find absolute extremes
of ion Encuentre los extremos absolutos de la función f(x) = 3x4 - 4x³ sobre el intervalo [-1,2]. Máximo absoluto Minimo absoluto Choose... Choose...3 answers -
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15 Find the derivation of a) y = t4-1 b) y = 1 Tx² 氣 C) y = 1x¹ cos(17²) d) f(2)= (1-e² ) (z+e²) e) x³ ty³ = 6xy1 answer -
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Find the particular solution of the differential equation. dy 2 6x - 4x + 19; y = 3 when x = 1 OA. y = 2x³ - 2x² +19x-16 OB. y = 2x³-4x² +19x - 14 OC. y = 2x³ - 2x² + 19x + 16 D. y = 6x² - 4x²1 answer -
(1 point) Suppose f(x, y) = xy² +8. Compute the following values: f(4, -2)= f(-2,4)= f(0,0)= f(-4,-2)= f(t, 4t)= f(uv, u-v)=1 answer -
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(1 point) Find the partial derivatives of the function fz(x, y) fy(x, y) = = fay(x, y) fyx (x, y) = = 6y f(x, y) = xye3 answers -
1) Evaluate 2) Present the process to find the derivative 3) Evaluate the integrals
1) Evalúe a) csch (In 3) b) cosh (0) 2) Presente el procesos para hallar la derivada. X a) f(x) = -senh ( – 3x) 6 b) f(x) = sech² (3x) 3) Evalúe los integrales. senh (x) a) [ -dx 1+ senh²(x) b)1 answer -
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Halle el polinomio de Taylor P3(x) de la función f(x) = arcsin(x), a = 0 Seleccione una: O a. 1+x+ O b. OC. ²/ -x+ ²/1²/2 x+ O d. x- -1 answer -
- (1 point) Let g(x, y, z) = x³y²z₁√√/10 − x − y — z. 1. Evaluate g(1, 2, 3). Answer: g(1, 2, 3) = 2. Evaluate g(-6, −2, 10). Answer: g(-6, −2, 10) : =3 answers -
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Dada la serie Seleccione una: O a. O b. OC O d. 11 1 1 13/2 1 1²/2 1 2 para determinar su divergencia se utiliza una serie con término n-ésimo b1 answer -
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Halle el intervalo de conferencia de la serie: (-1)- Seleccione una: O a. [-4,0] O b. (-4,0) OC. (-4,0] O d. [-4,0) (z+2)" n2" n=01 answer -
4) Determine where the function is continuous. a) f(x, y) = x² y √16-x² - y² ху b) ƒ(x, y) = { x² + xy + y² ›(x, y) ± (0, 0) 0, (x, y) = (0,0)1 answer -
Solve the initial value problem O y = tet O y = et + e O y = 8e + Ser O y = 8teft O y = et O y = 8er y" - 12y' + 36y = 0, y(0) = 0, y'(0) = 81 answer -
Evalue la integral f In(1-1) dt y expresela como una serie de potencias: Seleccione una: prot O a. Σα n=1 (n+1)² t-i-1 Ob. Σ -0 (n+1)² Oc O d. Σ 1 n=1 (n+1)² 88 41 an 0 (n+1)1 answer -
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Question 21 (d) X 01-1 1+4+ 16 02 +42 y O-21²-2y² + 2² = 1 0 # 9 2 HE SH = 0 0 x² - y² + 2² - 0 > 2² - #² = -y 11 answer -
Solve the initial value problem e-³t + 3e-3t 0y=e O y = 3e-³t+e-³t ○ y = e-³t cost + 3e-³t sint O y = cost + 3sint O y = O y = 3e-³t cost + e-³t sint = 3cost + sint b". + 6y' + 10y = 0, y(0)1 answer