Calculus Archive: Questions from December 23, 2022
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Example (6): Solve the initial-value problem (IVP) \[ \frac{d y}{d x}=2 x \cos ^{2} y \quad, \quad y(0)=\frac{\pi}{4} \]2 answers -
Evaluate f(2,1) and f(2.1, 1.05) for the following functions of two variables and calculate delta z. Use the total difference dz to approximate delta z. Pls write clearly Thnks!
Parte II: Evalúe \( f(2,1) \) y \( f(2.1,1.05) \) para las siguientes funciones de dos variables y calcular \( \Delta z \). Utice la diferenciación total dz para aproximar \( \Delta z \) : 1. \( f(x2 answers -
Evaluate \( \int_{0}^{a} \int_{\sqrt[3]{y}}^{a} \sin \left(x^{4}\right) d x d y \), where \( a=\sqrt[4]{\pi / 3} \)2 answers -
Calculate \( y^{(k)}(0) \) for \( 0 \leq k \leq 5 \), where \( y=7 x^{4}+a x^{3}+b x^{2}+c x+d \) (with a,b,c,d the constants) \[ \begin{array}{l} y^{(0)}(0)= \\ y^{(1)}(0)= \\ y^{(2)}(0)= \\ y^{(3)}(2 answers -
Calculate \( y^{(k)}(0) \) for \( 0 \leq k \leq 5 \), where \( y=8 x^{4}+a x^{3}+b x^{2}+c x+d \) (with a,b,c, \( \mathrm{d} \) the constants) \[ \begin{array}{l} y^{(0)}(0)= \\ y^{(1)}(0)= \\ y^{(2)}2 answers -
Parte I: Halle las ecuaciones simétricas de la recta normal a la superficie en el punto dado 1. \( x^{2}+y^{2}+z^{2}=9,(3,3,3) \) 2. \( z=x^{2}-y^{2},(3,2,5) \) 3. \( x y z=10,(1,25) \) 4. \( x y-z=00 answers