Calculus Archive: Questions from December 10, 2022
-
2 answers
-
how to do those exercises???
Objetivo: Esta actividad tiene como propósito de ayudar al estudiante a demostrar la convergencia o divergencia de 4 enésima suma, de las series geométricas y del enésimo término. (Objetivo 3) In2 answers -
9. Identify the horizontal asymptote of \( f(x)=\frac{\sqrt{9 x^{4}+25 x}+x^{2}}{x^{2}-9} \). [A] \( y=3 \) [B] \( y=8 \) [C] \( y=9 \) [D] \( y=0 \) [E] \( y=4 \)2 answers -
Let \( y \) be the solution of IVP \( y^{\prime \prime \prime}+3 y^{\prime \prime}+3 y^{\prime}+y=0, y(0)=1, y^{\prime}(0)=0, y^{\prime \prime}(0)=1 \). Then \( y(-1)= \) a. \( -e \) b.e c. \( 2 e \)2 answers -
Calculate \( \iint_{\mathcal{S}} f(x, y, z) d S \) For \[ x^{2}+y^{2}=9, \quad 0 \leq z \leq 9 ; \quad f(x, y, z)=e^{-z} \] \[ \iint_{\mathcal{S}} f(x, y, z) d S= \]2 answers -
7. If \[ \tan y=\frac{2}{x^{2}} \] find \( y^{\prime} \) when \( x=-1 \) A. 1 B. \( \frac{4}{5} \) C. \( \frac{-2}{5} \) D. \( \frac{2}{5} \) E. \( \frac{-4}{5} \)2 answers -
Q2 please *
2) Find the most general integral of the following. a) \( y=\frac{6}{x+1} \) b) b) \( y^{\prime}=2 \cdot \sin \sin (x)+9 x^{2}+8 \) c) \( y=-8 \cdot \sec \sec (x) \cdot \tan \tan (x)+x \) d) \( y=6 \c2 answers -
Question 4 Let \[ f(x, y, z):=\frac{\cos \left(121 x^{2}+121 y^{2}\right)-e^{209 x^{2}+209 y^{2}}+39 x^{6} y^{4}}{11 x^{2}+11 y^{2}}+z \cos (x) \text {. } \] Find \[ \lim _{(x, y, z) \rightarrow(0,0,22 answers -
2 answers
-
Q2. A, B, C and D please *
2) Find the most general integral of the following. a) \( y=\frac{6}{x+1} \) b) b) \( y^{\prime}=2 \cdot \sin \sin (x)+9 x^{2}+8 \) c) \( y=-8 \cdot \sec \sec (x) \cdot \tan \tan (x)+x \) d) \( y=6 \c4 answers -
2 answers
-
please need done on computer please. all parts all info there
2) Find the most general integral of the following. a) \( y=\frac{6}{x+1} \) b) b) \( y^{\prime}=2 \cdot \sin \sin (x)+9 x^{2}+8 \) c) \( y=-8 \cdot \sec \sec (x) \cdot \tan \tan (x)+x \) d) \( y=6 \c2 answers -
24. Solve the differential equation \( 7 e^{x} y^{2}=y \frac{d y}{d x} \) (a) \( y^{2}=-\frac{2}{7} e^{-x}+C \quad 7 e^{x} d x=\frac{y}{y^{2}} d \) \( \begin{array}{l}\text { (b) } y^{2}=14 e^{-x}+C \2 answers -
2 answers
-
\( \lim _{\text {a) }}^{\theta \rightarrow \frac{3 \pi}{2}^{-}} \tan (\theta) \) \( \lim _{\text {b) }} \tan (\theta) \) \( \lim _{\text {c) }} \tan \tan (\theta) \)2 answers -
Find the area bounded by \( y=\frac{3}{x} \) and \( y=-x+4 \) Find the derivative of the following functions: a.) \( y=\left(4 x^{3}+9 x-1\right)^{8} \) b.) \( y=\frac{(5 x+2)^{6}}{9 x+7} \) c.) \( y=2 answers -
Calcular el area de la elipse \[ \begin{array}{l} \frac{x^{2}}{169 \pi}+\frac{y^{2}}{\pi}=1 \\ \frac{x^{2}}{169}+y^{2}=\pi \\ y=\sqrt{\pi-\frac{x^{2}}{169}}-2 x \end{array} \] Answer:2 answers -
Find the first partial derivatives of the function. \[ f(x, y)=\frac{x}{y} \] \[ f_{x}(x, y)= \] \[ f_{y}(x, y)= \]2 answers -
Find \( y \) as a function of \( x \) if \[ \begin{array}{l} y^{\prime \prime \prime}-9 y^{\prime \prime}-y^{\prime}+9 y=0 \\ y(0)=-3, \quad y^{\prime}(0)=-2, \quad y^{\prime \prime}(0)=-323 \\ y(x)=2 answers -
(a)Calculate rotor of F (b) Is F conservative? if yes, why? (c) If F is conservative then find potential of f.
1. Consideremos el campo vectorial que está definido en todo el espacio: \[ F(x, y, z)=2 x y \hat{\imath}+\left(x^{2}+2 y z\right) \hat{\jmath}+\left(y^{2}+1\right) \hat{k} \] (i) Calcular el rotor d2 answers -
Find vectorial camos of F and G, one conservative and the other not, but that the divergence of both is satisfied
2. Encontrar dos campos vectoriales \( F \) y \( G \) uno conservativo y el otro no pero que la divergencia de ambos cumpla \[ (\nabla \cdot F)(x, y, z)=x+y+z=(\nabla \cdot G)(x, y, z) \]2 answers -
Calculate area of portion of the sphere of Radius R that is above semi cone z
3. Calcular el área de la porción de la esfera de radio \( R \) que está arriba del semicono \( z=\sqrt{x^{2}+y^{2}} \)2 answers -
Calculate portion of paraboloid z that is above plane z=0
4. Calcular el área de la porción del paraboloide \( z=1-x^{2}-y^{2} \) que está arriba del plano \( z=0 \).2 answers -
2 answers
-
For Vectorial camp F and surface that is part of paraboloid z= 1-x^2-y^2 that is above plane z=0. Verify stokes theorem
5. Para el campo vectorial \[ F=\langle-y, x, z\rangle \] la superficie que es la parte del paraboloide \[ z=1-x^{2}-y^{2} \] que está arriba del plano \( z=0 \) verificar el Teorema de Stokes.2 answers