Calculus Archive: Questions from April 09, 2022
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dx = dy 1. [20 Marks]. Determine for each of the following. (a) y = 2cos3x (b) y = sin 3x – cos4x (c) y = 2 + 2sinx 2cosx (d) y = 2sinxcosx (e) y = eX(cosx + sinx) (f) y = 2x’sinx – 3xcosx (g) y1 answer -
Problem #1: Find the domain of the function f(x, y) = In(4x2 – 4y +1). = The set of all ordered pairs (x, y) for which: +4x2 (B) y = 1 + 4x2 (B) y < 1 + 4x2 1 (D) y 2 1 +4x2 (E) y > -1 + 4x2 ) 4 F 41 answer -
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Complete the table. y = f(g(x)) u = g(x) y = f(u) y - y = (9x – 8)5 lu = - ly= u5 = Need Help? Read It 2. [-/1 PUNTOS] DETALLES LARCALC11 2.4.008. u = g(x) Complete the table. y = f(g(x)) 9x y = sin1 answer -
Part 1: Determine the derivative direction in direction of the unit vector u = (cos 0, sin0). Part 2: Determine the directional derivative of the function at P in the direction of Q.
= Parte 1: Determine la derivada dirección en dirección del vector unitario ū = (coso, seno) 1. f(x,y) = x2 + y2, 0 = 1/4 2. f(x,y) = sen (2x + y), 0 = 1/3 Parte II: Determine la derivada direcci1 answer -
Part 3: Find the gradient of the function at P and use it to find the directional derivative of the direction of Q. Part 4: Find the gradient of the function and the maximum value of the directional
Parte III: Halle el gradiente de la función en P y utilícelo para hallar la derivada direccional de la dirección de Q. = 1. g(x,y) = x2 + y2 + 1, P(1,2) y Q(2,3) 2. f(x,y) = esen(x), P(-1,4) y Q(3,1 answer -
(1 point) Evaluate SS/B f(x, y, z) dV for the specified function f and B: z f(x, y, z) = 3 < x < 24,0 < y < 3,0 < z < 4 х SITB f(x, y, z) DV = =1 answer -
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= ety dy Find the general solution to the differential equation dx O A. y = x + C B. y = (In x) + C OC. y = ln(x + C) OD. y = ln(e* + C) E. y = C ln x1 answer -
Solve the following differential equation. y" + y = 62, y0) = 0, y (0) = 1 e' O 1 (t) = e + + - 1 COS 5 sin 1 VI) =-e2 cosesini 1 1 -COS 1 + - sin 1 1 3 9 y J(0) = ལ cos7 + རྗེin/ 1 3 y(t) ) c1 answer -
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= x 18: Solution of the DE: xy' + 2 x y = ln(x). . A In(x)-1 y = C + B C C In(x) -1 y = - + x C C 2ln(x) - 1 y = x2 + 4 D In(x) - 1 y = C + x2 220 answers -
4. Solve each initial-value problem. (a) 7" + 4y = t; y(0) = 0, 7(0) = 0, y"0) = 1 (b) y" + y = sect, -*/21 answer