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Mira la respuestaMira la respuesta done loading Muestra el texto de la transcripción de la imagenPregunta: V(x)=∞ if ∣x∣>a+bV(x)=0 if a≤∣x∣≤a+bV(x)=V0 if ∣x∣
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To analyze the potential V(x) described in your question and study its solutions, we can follow thes...
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Texto de la transcripción de la imagen:
V(x)=∞ if ∣x∣>a+bV(x)=0 if a≤∣x∣≤a+bV(x)=V0 if ∣x∣<a (a) Show that the energy eigenvalues for this potential are given by the equations: tanbk=−κkcothaκ, for even solutions, and tanbk=−κktanhaκ, for odd solutions with, k=ℏ22mE and κ=ℏ22m(V0−E) (b) Study the solutions where V0→∞ and show that the odd and even solutions give the energy spectrum of an "ordinary box", corresponding to two atoms which are not interacting. (c) Also, for the solutions where V0→E, show that the odd and even solutions give slightly different energy levels, such that the energy spectrum will consist of pairs of close energy levels. For many such adjacent boxes this would give a band of energies. (d) Show that a→0 gives the same energy spectrum as an ordinary box with width 2b.
V(x)=∞ if ∣x∣>a+bV(x)=0 if a≤∣x∣≤a+bV(x)=V0 if ∣x∣<a (a) Show that the energy eigenvalues for this potential are given by the equations: tanbk=−κkcothaκ, for even solutions, and tanbk=−κktanhaκ, for odd solutions with, k=ℏ22mE and κ=ℏ22m(V0−E) (b) Study the solutions where V0→∞ and show that the odd and even solutions give the energy spectrum of an "ordinary box", corresponding to two atoms which are not interacting. (c) Also, for the solutions where V0→E, show that the odd and even solutions give slightly different energy levels, such that the energy spectrum will consist of pairs of close energy levels. For many such adjacent boxes this would give a band of energies. (d) Show that a→0 gives the same energy spectrum as an ordinary box with width 2b.
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