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  • Pregunta: i=CVi(t)=CdtdV Capacitor 1 C1Vc1=i1−i2 Ley de Kirchhoff ∑V=0 Capacitor 2 C. Vc2=i2 C1Vc1=i1−i2i1=C1⋅VC1+i2→i1=C1⋅Vci2=C2⋅VC2i1=C1i2=C i2=C2dtdvC2i=CVi(t)=CdtdVc Capacitor 1 Vc1=i1−i2 Malla 1 Capacitor 2 C2VC2=i2Vc1= ? dtdVcC1vc1=i1−i2i1=C1⋅VC1+i2+i1=C1⋅VC1+C2⋅VC2i1=C1⋅dtdVc1+C2dtdVc2dtdVc2Vc2= ? L2=CiVc2dtdVc2Vc2=?i2=C2dtdVc2


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    Texto de la transcripción de la imagen:
    i=CVi(t)=CdtdV Capacitor 1 C1Vc1=i1i2  Ley de Kirchhoff V=0 Capacitor 2  C. Vc2=i2 C1Vc1=i1i2i1=C1VC1+i2i1=C1Vci2=C2VC2i1=C1i2=C i2=C2dtdvC2 i=CVi(t)=CdtdVc Capacitor 1 Vc1=i1i2 Malla 1 Capacitor 2 C2VC2=i2Vc1= ? dtdVcC1vc1=i1i2i1=C1VC1+i2+i1=C1VC1+C2VC2i1=C1dtdVc1+C2dtdVc2dtdVc2Vc2= ? L2=CiVc2dtdVc2Vc2=?i2=C2dtdVc2
Texto de la transcripción de la imagen:
i=CVi(t)=CdtdV Capacitor 1 C1Vc1=i1i2  Ley de Kirchhoff V=0 Capacitor 2  C. Vc2=i2 C1Vc1=i1i2i1=C1VC1+i2i1=C1Vci2=C2VC2i1=C1i2=C i2=C2dtdvC2 i=CVi(t)=CdtdVc Capacitor 1 Vc1=i1i2 Malla 1 Capacitor 2 C2VC2=i2Vc1= ? dtdVcC1vc1=i1i2i1=C1VC1+i2+i1=C1VC1+C2VC2i1=C1dtdVc1+C2dtdVc2dtdVc2Vc2= ? L2=CiVc2dtdVc2Vc2=?i2=C2dtdVc2