Algebra Archive: Questions from March 21, 2023
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\( \begin{array}{l}T(x, y)=(4 y-2 x, y+1,-3 x y) \\ T(x, y, z)=(y-x-z,-x) \\ T(x, y)=(y+2 x, 2 x, 3 y-x) \\ T(x, y)=(2 y-x, 2 y 1) \\ T(x, y, z)=(2, x, 4 y)\end{array} \) (1 pt) Determine which of th2 answers -
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4. Differentiate the following functions: (a) \( y=6 \ln \sqrt[3]{x} \) (b) \( y=7 e^{x} \) (c) \( y=e^{x^{2}+1} \) (d) \( y=e^{\ln x} \)2 answers -
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Solve for \( x \) and \( y \) if \[ \left|\begin{array}{ccc} 1 & 1+2 j & 0 \\ 1-j & -1 & -1 \\ x & 0 & y j \end{array}\right|=2 j \]2 answers -
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Simplifica la expresión \( \frac{x^{3}+2 x^{2}-x-2}{x^{2}+5 x+6}=( \) ) Pista: encuentra un factor lineal que sea común al numerador \( y \) al denominador. EI denominador es fácil de factorizar, p2 answers -
Suponer \[ f(x)=\frac{7 x+2}{x^{2}+x-2} \] Entonces \[ f(x)=\frac{A}{x-1}+\frac{B}{x+2} \] donde \( \mathrm{A}= \) \[ \text { y } B= \]2 answers -
\[ \begin{array}{ll} \frac{1}{x+1}+\frac{1}{x+8}=( & ) /( \\ \frac{1}{x+1}-\frac{1}{x+8}=( & ) /( \\ \frac{1}{x+1} \times \frac{1}{x+8}=( & ) /( \\ \frac{1}{x+1} \div \frac{1}{x+8}=( & ) /( \end{array2 answers -
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