Algebra Archive: Questions from January 04, 2023
-
Current Attempt in Progress Compute \( \left(T_{3} \circ T_{2} \circ T_{1}\right)(x, y) . T_{1}(x, y)=(-4 y, 5 x, x-4 y) \), \( T_{2}(x, y, z)=(y, z, x), T_{3}(x, y, z)=(x+z, y-z) \). \( \left(T_{3} \2 answers -
Compute \( \left(T_{3} \circ T_{2} \circ T_{1}\right)(x, y) . T_{1}(x, y)=(-4 y, 5 x, x-4 y) \), \[ T_{2}(x, y, z)=(y, z, x), T_{3}(x, y, z)=(x+z, y-z) \text {. } \] \[ \left(T_{3} \circ T_{2} \circ T2 answers -
Compute \( \left(T_{2} \circ T_{1}\right)(x, y) \). \[ T_{1}(x, y)=(8 x,-7 y, x+y), T_{2}(x, y, z)=(x-y, y+z) \] \[ \left(T_{2} \circ T_{1}\right)(x, y)=( \]2 answers -
Compute \( \left(T_{2} \circ T_{1}\right)(x, y) \). \[ \begin{array}{c} T_{1}(x, y)=(6 x,-5 y, x+y), T_{2}(x, y, z)=(x-y, y+z) \\ \left(T_{2} \circ T_{1}\right)(x, y)=\left(\begin{array}{c} \end{array2 answers -
2 answers