Algebra Archive: Questions from November 27, 2022
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2 answers
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Solve the system of equations: \[ \begin{array}{l} x+y=5 \\ 2 x-3 y=15 \end{array} \] \[ x=-1, y=6 \] \[ x=6, y=-1 \] \[ x=0, y=5 \] \[ x=3, y=2 \]2 answers -
Solve the system of equations: \[ \begin{array}{l} 7 x-5 y=9 \\ -6 x+5 y=-2 \end{array} \] \[ x=7, y=8 \] \[ x=-2, y=-2 \] \[ x=5, y=5 \] \[ x=3, y=4 \]2 answers -
QUESTION 1 QUESTION 2 QUESTION 3 QUESTION 5 F actor completely. Factor completely. Factor completely. Factor completely. \( 13 x^{2}-133 x+30 \) \( a^{2}+a b-12 b^{2} \) \( w(x+y)^{2}+3 w(x+y)+2 w \)2 answers -
Compute (T2 o T1) (x,y).
Compute \( \left(T_{2} \circ T_{1}\right)(x, y) \). \[ \begin{array}{c} T_{1}(x, y)=(4 x,-4 y, x+y), T_{2}(x, y, z)=(x-y, y+z) \\ \left(T_{2} \circ T_{1}\right)(x, y)=(\mid) \end{array} \]2 answers -
Is \( \mathrm{y} \in \operatorname{span}(S) \) where \[ \mathbf{y}=\left(\begin{array}{c} -3 \\ 0 \\ 5 \end{array}\right), \quad \text { and } \quad S=\left\{\left(\begin{array}{l} 1 \\ 2 \\ 3 \end{ar2 answers -
\[ \left\{\begin{array}{ll} y-6 x & =-13 \\ 2 y & =12 x-26 \end{array}\right. \] Answer: \( (x, y)=1 \)2 answers -
Find \( A C \), if possible. \[ A=\left[\begin{array}{rrr} 1 & -2 & 1 \\ 0 & 2 & -1 \end{array}\right] \quad C=\left[\begin{array}{rrr} -1 & 0 & 1 \\ 2 & -5 & 1 \\ -2 & 3 & 5 \end{array}\right] \]2 answers