Algebra Archive: Questions from December 04, 2022
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2 answers
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finding all unkows n1,n2,n3,n4,n5
\[ \frac{n_{3}}{n_{2}}=3, \frac{n_{2}}{n_{4}}=0.1, \frac{n_{3}}{n_{4}}=0.3 \] \( 2 n_{5}=2 n_{3}+n_{4} \) (eq2) \( 0.2 A+n_{5}=n_{2}+n_{3}+78 \) (eq3) \( 3.6 A=2 n_{5}+4 n_{1}+2 n_{2}+2 n_{4} \) \( \l2 answers -
Find \( x \) and \( y \). \[ \left[\begin{array}{rr} -2 & 3 x \\ y & 2 \end{array}\right]=\left[\begin{array}{ll} -2 & 6 \\ -7 & 2 \end{array}\right] \] \[ x= \] \[ y= \]2 answers -
1. Find the following for the function \( f(x, y)=3 x^{3} y^{2}-5 x+26 y-9 \). a. \( f(1,2)= \) b. \( f_{y}(x, y)= \) c. \( f_{x}(x, y)= \) d. \( f_{x}(1,2)= \) e. \( f_{y y}(x, y)= \) f. \( f_{x x}(x2 answers -
5. (20.4 \#16) Solve the initial value problem. \[ \mathbf{y}^{\prime}=\left[\begin{array}{ll} -7 & 4 \\ -6 & 7 \end{array}\right] \mathbf{y}, \quad \mathbf{y}(0)=\left[\begin{array}{r} 2 \\ -4 \end{a2 answers -
2 answers
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all work \[ \left\{\begin{array}{c} y=3 x-6 \\ -2 x+3 y=10 \end{array}\right\} \] \[ (4,6) \] \[ y=-7 x+3 \]2 answers -
2 answers