Advanced Math Archive: Questions from January 08, 2023
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16. The solution of the IVP \( y^{\prime}=e^{-x-y}, y(-\ln 3)=\ln 3 \), is (A) \( y=\ln \left|6+e^{-x}\right| \) (B) \( y=-x \) (C) \( y=\ln \left|4-e^{-x}\right| \) (D) \( y=\ln \left|4+e^{-x}\right|2 answers -
SOLVE BY METHOD OF UNDETERMINED COEFFICIENTS
\( (3 x+2)^{2} y^{\prime \prime}+3(3 x+2) y^{\prime}-36 y=3 x^{2}+4 x+1 \)2 answers -
2 answers
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2 answers