Advanced Math Archive: Questions from December 20, 2023
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Resolver
La temperatura \( u(x, t) \) d'una varilla de longitud \( L \) ve donada per: \[ \begin{array}{c} \frac{K}{\gamma \rho} \frac{\partial^{2} u(x, t)}{\partial x^{2}}-\frac{\partial u(x, t)}{\partial t}=1 answer -
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Simplify. \[ \begin{array}{c} \frac{15 a^{3} b}{-14} \times \frac{-28 a b^{-1}}{9 a^{5} b^{2}} \\ \frac{10}{3 b^{2}} \\ -\frac{20 a}{6 b^{2}} \\ \frac{10 a^{4}}{3 a^{5} b^{2}} \\ \frac{10}{3 a b^{2}}1 answer -
\( \begin{array}{c}\frac{15 a^{3} b}{-14} \times \frac{-28 a b^{-1}}{9 a^{5} b^{2}} \\ \frac{10}{3 b^{2}} \\ -\frac{20 a}{6 b^{2}} \\ \frac{10 a^{4}}{3 a^{5} b^{2}} \\ \frac{10}{3 a b^{2}}\end{array}1 answer -
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