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Advanced Math Archive: Questions from March 18, 2022

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  dzy - 1) 4Y dx² + 4y cosex yllo) a =coh y JO II
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  QUESTION 6 Find the linear approximation of the function y = x3 at point xo = 1 = a. . y = 3x – 2 b. y = 3x - 1 y = 3x + 2 C.
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  A = {a, b, c, d, e, f, g, x, y, z}, B = {c,r,a, z, y}. (a) n(A) (b) n(B) (c) n(ANB) (d) n(AUB)
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  Find the general solution of the equation 2 dy dy y + 2 d.x2 dc = 0. (a) y= (Ci sin x + C2 cos x) -1/3 (b) y= (Ci sin x + C2 cos x)/3 (c) y = (C12 - C2)-1/3 (d) y = (C1x + C2)-1 y ) (e) y = (Cur+C2)1/
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• There is a hexagon of side L (Fig.1) through which a current I (counterclockwise direction) circulates. The Hexagon is circumscribed within a square of side L1 through which a current I flows in a clo
  1) Se tiene un exágono de lado L (Fig. 1) por el cual circula una corriente 1 (dirección antihoraria). El exágono está circunscrito dentro de un cuadrado de lado Lı por el cuál circula una corri
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• Please answer question #30 and #33
  30. 7'' – 27" + y = 2ez + 2x, y(0) = 0, y'(0) = 0, "(0) = 0. y 2y ' 21 0,7 31. y' + 9y = 8 cos I, y(*/2) = -1, y' (1/2) = 1. ' 32. 7" – 5y' + 6y y = e+(21 – 3), y(0) = 1, y'(0) = 3. 33. 7" – 3
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• number # 9 , 11 , 19 , 21
  Use identities to find each exact value. See Example 1. 577 9. sin 1377 10. sin 11. tan 12 12 12 TT 57 12. tan 12 777 13. sin 12 14. sin TT 12 15. sin 77 12 (一) an(-1 16. sin 5T 12 17. tan ( 5TT 12
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  6) Resuelva la ecuación diferencial dada sujeta a las condiciones iniciales dadas: dạy dy +692 + 5y = 0 , = y(0) = 0, y'(0) = 3 dx dx2
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  E1. Solve the initial value problem y" – y' - 6 yr e-t u4(t), y(0) = 0, y'(0) = - = 1. E2. Solve the initial value problem = y" + 4 y' +5 y= t uz(t), 0. y(0) = 0, y'(0) = =
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  Moving to another Question will reprise Questions Considerada de compra y 10 de ago sestancia horizontal que esta con las condiciones intem Moving to another questo BEN D
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• draw a signal flow graph for the following equation of state
  4) Dibujar un gráfico de flujo de señal para la siguiente ecuación de estado 0 1 0 X= 0 0 1x + or 1-2 -4 -6 y = [1 1 = 1 0] X 4) Dibujar un gráfico de flujo de señal para la siguiente ecuación
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• SOLVE the following DIFFERENTIAL EQUATIONS.
  en + yż = 1, when x = 0, y = 4 04 = dx cos(x + y), when x = 0, y = 5
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  Solve the following initial value problem. y" - 4y" + 5y' = 150 e 5*, y" (0) = 91. y' (O) = 19, y(0) = 9 y(x)=
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  Draw some of the features - = X>0, y> 0 sur — yuz = u - y u(y?, y) = y = Y>0
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