Advanced Math Archive: Questions from June 11, 2022
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Find f'(x) f(x)=cos³(2x-1) tan²4(3x + 1) O f(x)=6cos²(2x-1) tan³(3x + 1)[-sin(2x - 1)tan(3x+1)+2cos(2x - 1)sec 2(3x + 1)] f(x)=6cos²(2x - 1) tan³(3x + 1)[sin(2x - 1)tan (3x + 1) +2cos(2x - 1)sec1 answer -
Convert the ratio scale to a verbal scale. 1:24,000 1 inch=_______miles 0.240,000 mi 4.54 mi 0.5280 mi 0.378 mi 5280 mi1 answer -
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1 ) x ( 1 + y²³) dx = y(1+x²) dy 2) y = x tgj 3.) √y² + 1 dx = xydy 4² x √² + y²³ dx + √ √ ₁ + x²dy = 0, y(o)= 0 27 5 y Sinx = sin y, y (중)= 쫓 3 6² xy²= y + √x² + y² 2 2 71 answer -
1. y 2- y" = xe 3- 2xy'y" = (y')² + 1 (without Y) 3 4 y" - 2ctgx. y' = Sin ³x (without Y) 5. yy" = (y¹) ³² (without X) |yy" — (y)² = y^y' (without X) 7|y" - Gy' + 5y = D 6. 8- y" — 41' = 0 91 answer -
3x + 2. y" - y = 2 sin x - 4 CDs x 3) y" + 4y² + 5y = 1Dx² +x+2 3x 4 y" - 5y + 6y=2e² te 2 5. y" — 5y¹ -6y= 7e¯* + 6x² - 2x1 answer -
SELECCIONE LA RESPUESTA CORRECTA Resuelva (1+x² + y² + x²y²) dy=y²dx 1 A y- - arctan x= C y B y-y-¹-ln(x² +1)=c y-y² -ln(x² +1)=c 1 y+-+arctan x = c y In(1+y²)-arctanx=c C D E1 answer -
One of the following is periodic boundary conditions: Select one: y(a) = y(b) & y' (a) = y' (b) b. y' (a) = 0 & y' (b) = 0 C. y(a) + y'(a) = 0 & y(b) + y' (b) = 0 d. y(a) + y(b) = 0 & y' (a) + y' (b)1 answer -
for the following system, find if it is observable and/or controllable
Para el siguiente sistema, encuentra si es observable y/o controlable 2 3 X(X + 1) = [ 0 ? ? ] x [(~) + [1] u(x) 2 y (K) = [2 4 1] x (K) + [5] U(K) 20011 answer -
1. Find the spectrum (magnitude and phase) of the system represented by the following function of transference. Graph the magnitude in dB versus log f and the phase versus log f where f=2000 Hz. Limit
1. Encuentra el espectro (magnitud y fase) del sistema representado por la siguiente función de transferencia. Grafica la magnitud en dB versus log fy la fase en grados versus log f, suponiendo una f1 answer -
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Solve the given differential equation. Find the explicit solution when possible. I (1) y' = y(0) = -2 y +² (2) y' = y+t³y (3) y′ = y² + 4te²ty², y(0) = -1 (4) y'=xsin x + xy² sinx, y(0) = 1 (50 answers -
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