Advanced Math Archive: Questions from August 08, 2022
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What is the second derivative of \( y=2 e^{4 x} \) ? A. \( y^{*}=32 e^{4 x} \) B. \( y^{*}=8 e^{4 x} \) C. \( y^{n}=2 e^{4 x} \) D. \( y^{\prime \prime}=8 e^{3 x} \)1 answer -
Given \( y=2 \sqrt{x}-\frac{1}{x} \) find \( y^{\prime} \) A. \( \sqrt{x}-x^{2} \) B. \( \sqrt{x}+\frac{1}{x^{2}} \) C. \( \frac{1}{\sqrt{x}}+\frac{1}{x^{2}} \) D. \( \frac{1}{\sqrt{x}}-\frac{1}{x^{2}3 answers -
Given \( y=2 \sqrt{x}-\frac{1}{x} \) find \( y^{\prime} \) A. \( \sqrt{x}-x^{2} \) B. \( \sqrt{x}+\frac{1}{x^{2}} \) C. \( \frac{1}{\sqrt{x}}+\frac{1}{x^{2}} \) D. \( \frac{1}{\sqrt{x}}-\frac{1}{x^{2}1 answer -
Just tell me which number thank u
Match the graph with its function. \( 2 . \) \( y=\frac{x}{x^{2}-9} \) \( y=\frac{1}{x^{2}-9} \) \( y=-\frac{1}{x-3} \) \( 3 . \) \( y=\frac{x-2}{x-3} \) \( y=\frac{x-2}{x-3} \)1 answer -
Deducir que si aproximamos el polinomio de orden 2 de Taylor \( T^{(2)}(t, y)=f(t, y)+\frac{h}{2} f^{\prime}(t, y) \) mediante \( a_{1} f(t, y)+a_{2} f\left(t+\alpha_{2}, y+\delta_{2} f(t, y)\right) \1 answer -
c,d ,f with process.
1. Differentiate the following functions: (a) \( y=x^{2}+x^{50} \) (b) \( y=x^{3}+3 \) (c) \( y=x-\frac{1}{x^{2}} \) (d) \( y=50-\frac{1}{x^{3}} \) (e) \( y=3 x^{5}+2 x^{3} \) (f) \( y=2 \sqrt{x}+\fra1 answer -
Solve Laplace's equation, \( \frac{\partial^{2} u}{\partial x^{2}}+\frac{\partial^{2} u}{\partial y^{2}}=0,01 answer -
1) Solve the following IVPs: a) \( y^{\prime}=\frac{2 t}{\sin y} \), \( y(1)=\pi \) b) \( x y^{\prime}+y=2 x \cos x \) \( y(\pi)=0 \)1 answer -
Write the given system in the form \( \mathbf{x}^{\prime}=\mathbf{P}(\mathrm{t}) \mathbf{x}+\mathbf{f}(\mathrm{t}) \). \[ \begin{array}{l} x^{\prime}=3 x-4 y+z+t \\ y^{\prime}=x-5 z+t^{2} \\ z^{\prime1 answer -
Consider the Boundary Value problem \[ \begin{array}{l} \frac{\partial^{2} u}{\partial x^{2}}+\frac{\partial^{2} u}{\partial y^{2}}=0, \quad 01 answer -
Consider the Boundary Value problem \[ \begin{array}{l} \frac{\partial^{2} u}{\partial x^{2}}+\frac{\partial^{2} u}{\partial y^{2}}=0, \quad 01 answer -
In the following Laplace equation the result is:
POR 17 PUNTOS. Al resolver la siguiente ecuación diferencial utilizando la transformada de Laplace \( y^{\prime \prime}-4 y^{\prime}+4 y=t^{3} e^{2 t} ; \quad y(0)=0, \quad y \prime(0)=0 \) , obtenem1 answer -
When solving the following differential equation using the Laplace transform, we can be sure that the zeros of this equation correspond to ?
POR 11 PUNTOS. Al resolver la siguiente ecuación diferenciales utilizando la transformada de Laplace \( y^{\prime}-y=t^{e t} ; \quad y(0)=0 \), podemos asegurar que los ceros de dicha ecuación corre1 answer -
(1 point) Solve the initial value problem \[ y^{\prime \prime}+1 x y^{\prime}-4 y=0, y(0)=9, y^{\prime}(0)=0 \] \[ y= \]3 answers -
3 answers