Advanced Math Archive: Questions from April 14, 2022
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1 answer
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Which of the following is the solution of the initial value problem + 4y(4) + 4y(3) = 0, y(5) 1 y, y y(0)=0 , /(0)=-, 32(0)=5, y®(0)=-14, y()) y(4)(O)=36 ? 2 y = -1 t2 + 2 te-2t y = t2 t + 4 1 4 e -t1 answer -
A drug is injected into a person's bloodstream at a constant rate of r grams per second. Simultaneously, the drug is eliminated at a rate proportional to the amount of drug x(t) present at each instan
Question 2 Una droga se inyecta en el torrente sanguíneo de una persona con por segundo. Simultáneamente la droga se elimina con una rapidez droga x(t) presente en cada instante. Formule una ecuaci1 answer -
The Turin mantle shows the negative of the image of the body of a man who appears to have been crucified, many people believe that it is the burial shroud of Jesus of Nazareth. In 1998 the Vatican gra
uestion 2 2 points Save Answe El manto de Turin muestra el negativo de la imagen del cuerpo de un hombre que parece que fue crucificado, muchas personas creen que es el sudario del entierro de Jesús1 answer -
Determine a model that describes the population of a country when immigration is allowed at a constant rate of r.
Question 4 Determine un modelo que describa la población de un país cuando se permite la inmigración con una tasa constanter. dP = P + dt dP = kP-r dt dP =kurP dt dP KP dt Ninguna de las anteriores1 answer -
A tank contains 200 liters of a liquid in which 30 g of salt have been dissolved. Another salt mix that has 1 gallon of salt per liter enters the tank at a rate of 4 L/min. The well-mixed solution lea
2 points Save Answer Un tanque contiene 200 litros de un liquido en el que se han disuelto 30 g de sal. Otra mezcla de sal que tiene 1 galón de sal por litro entra al tanque a una razón de 4L/min. L1 answer -
sinusoidal functions
Which equation below fits the graph? 3 7 6 5 4 3 10/11 a) y = - 4 sin(x - 1) + 2 Ob) y = - 4 sin(x + 1) - 2 c) y = 4 sin(x - 1) - 2 2 9 111 a) y = - 4 sin(x - 1) + 2 b) y = - 4 sin(x + 1) - 2 c) y =1 answer -
1, 3, 7 for a Like
- In Problems 1-12 use the Laplace transform to solve the given initial- value problem. 1. y' - 3y = 8(t - 2), y(0) = 0 2. y' + y = 8(t – 1), y(0) = 2 3. y" + y = 8(t - 27), y(0) = 0, y'(0) = 1 4. y1 answer -
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de [X' J, (ax)] = x"J,–1(ax), v 20, a > 0, So 2º J3 (2x) dx = Given the Bessel identity 1 α dr 2 26 O a) 32J4(4) – 16J5 (4) b) 64J3 (4) Od 16J/(4) – 8J (4) c) ( Od 64J (4) – 32J$(4) ) ke) No1 answer -
1) Consider the function (1) Find a linear homogeneous differential equation of third order with constant coefficients so that the function (1) is a solution of that differential equation. 2) If its
1) Considere la función: (4 puntos) y=Cie?+ + Cre?: +Cge-62 (1) Encuentre una ecuación diferencial lineal homogénea de tercer orden con coeficientes constantes de modo que la función (1) sea soluc1 answer -
Consider the differential equation (3): a) Determine the characteristic equation φ(m) = 0 associated with the differential equation (3) b) Completely factor the characteristic polynomial φ(m). c)
3) Considere la ecuación diferencial: 75) + 4y") - 7" - 147" +10y = 0 (3) a) Determine la ecuación caracteristica o(m) = 0 asociada a la ecuación diferencial (3). (1 punto) b) Factorice completamen1 answer